Javafx ContextMenu如何获得单击对象?

 2023-02-17    481  

问题描述

我正在学习javafx.scene.control.contextmenu,现在我面临一个问题:

如何从EventHandler中获取单击对象? event.source()和event.target()返回menuitem.

Javafx ContextMenu如何获得单击对象?

让我用一个例子解释:
我应该在函数句柄中写什么?

TextField text = new TextField();
    Label label1 = new Label("hello");
    Label label2 = new Label("world");
    Label label3 = new Label("java");

    ContextMenu menu = new ContextMenu();
    MenuItem item = new MenuItem("copy to text field");
    menu.getItems().add(item);
    item.setOnAction(new EventHandler(){
        public void handle(Event event) {
            //I want to copy the text of the Label I clicked to TextField
            event.consume();
        }
    });

    label1.setContextMenu(menu);
    label2.setContextMenu(menu);
    label3.setContextMenu(menu);

编辑:我希望有一些简单的解决方案(一个衬里),但是如果没有很多复杂的方法.

推荐答案

您可以创建自己的ContextMenu实例,并将操作父添加到其上以供进一步参考:

public class Main extends Application {

    TextField text = new TextField();

    public static void main(String[] args) {
        Application.launch(args);
    }

    @Override
    public void start(Stage primaryStage) {


        Label label1 = new Label("hello");
        Label label2 = new Label("world");
        Label label3 = new Label("java");

        label1.setContextMenu(new MyContextMenu(label1));
        label2.setContextMenu(new MyContextMenu(label2));
        label3.setContextMenu(new MyContextMenu(label3));

        HBox root = new HBox();

        root.getChildren().addAll(text, label1, label2, label3);

        Scene scene = new Scene(root, 300, 100);

        primaryStage.setScene(scene);
        primaryStage.show();

    }

    private class MyContextMenu extends ContextMenu {

        public MyContextMenu(Label label) {

            MenuItem item = new MenuItem("copy to text field");
            item.setOnAction(event -> {

                // I want to copy the text of the Label I clicked to TextField
                text.setText(label.getText());

                event.consume();
            });

            getItems().add(item);

        }

    }
}

其他推荐答案

我认为最简单的方法是将节点保存为上下文菜单的用户数据.

EventHandler<? super ContextMenuEvent> eventHandle = e->menu.setUseData(e.getSource());
label1.setOnContextMenuRequested(eventHandle );
label2.setOnContextMenuRequested(eventHandle );
label3.setOnContextMenuRequested(eventHandle );

和行动:

EventHandler<ActionEvent> menuItemEvent = e->{
    Node node = (Node) ((MenuItem)e.getSource()).getParentPopup().getUserData();
   ...
};

其他推荐答案

总结基本要求:掌握打开contextMenu的节点.根据Popupwindow的API Doc(ContextMenu的祖父母)的说法,这应该很容易实现

show(节点节点,…)

…弹出窗口与指定的所有者节点相关联…

noreflow noreferrer”> node getownernode() >

该弹出窗口的所有者的节点.

因此,menuitem作用的一般方法是

  • 掌握该物品的parentpopup(这是上下文menu),如果有嵌套菜单
  • 抓住自己的股
  • 访问所需的任何属性

最后,该示例仅在磁带文本和验证中,它是按预期工作的…如果我们使用控件的Contection -Menuproperty,我们是 不是.在控件中不工作的原因是方法违反方法(可能是由错误引入的修复 contextMenu的textInputControls中的自动嵌套行为):在将其设置为ContectionMenu之后,它始终使用show(Window w, ..)将其设置为任何控件(实现详细信息:control.contextmenuproperty设置了flag setShowRelativeToWindow(true)触发错误的flag setShowRelativeToWindow(true) -Behavior)

现在我们该怎么做才能掌握自己的股票?有几个选项,没有一个很好:

  • 正如其他答案中所做的那样,以某种方式跟踪了自有的诺德:通过使用工厂方法,通过存储在用户属性或任何其他临时含义
  • 扩展contextMenu,覆盖show(Node owner, … )并将给定的所有者保留在自定义属性中
  • 扩展contextMenu,覆盖show(Node owner, …)弄脏并反射性地将超级自己股设置为给定
  • 肮脏并反射重置有问题的showrelativetowwowlaw flag回到false 将菜单设置为任何控件

前两个引入了额外的耦合,后者(除了肮脏的反射访问)可能会重新引起自动隐藏的问题(“固定”行为本身是肮脏的..违反”守护者” – 插入”保证)

最后,一个示例要播放:

public class ContextMenuOwnerSO extends Application {

    private Parent createContent() {

        TextField text = new TextField();
        // the general approach to grab a property from the Node
        // that the ContextMenu was opened on
        EventHandler<ActionEvent> copyText = e -> {
            MenuItem source = (MenuItem) e.getTarget();
            ContextMenu popup = source.getParentPopup();
            String ownerText = "<not available>";
            if (popup != null) {
                Node ownerNode = popup.getOwnerNode();
                if (ownerNode instanceof Labeled) {
                    ownerText = ((Label) ownerNode).getText();
                } else if (ownerNode instanceof Text) {
                    ownerText = ((Text) ownerNode).getText();
                }
            }
            text.setText(ownerText);
        };

        MenuItem printOwner = new MenuItem("copy to text field");
        printOwner.setOnAction(copyText);

        // verify with manual managing of contextMenu
        Text textNode = new Text("I DON'T HAVE a contextMenu property");
        Label textNode2 = new Label("I'm NOT USING the contextMenu property");
        ContextMenu nodeMenu = new ContextMenu();
        nodeMenu.getItems().addAll(printOwner);
        EventHandler<ContextMenuEvent> openRequest = e -> {
            nodeMenu.show((Node) e.getSource(), Side.BOTTOM, 0, 0);
            e.consume();
        };

        textNode.setOnContextMenuRequested(openRequest);
        textNode2.setOnContextMenuRequested(openRequest);

        Label label1 = new Label("I'm USING the contextMenu property");

        ContextMenu menu = new ContextMenu() {

            // force menu to have an owner node: this being the case, it is not hidden 
            // on mouse events inside its owner
            //@Override
            //public void show(Node anchor, double screenX, double screenY) {
            //    ReadOnlyObjectWrapper<Node> owner = 
            //            (ReadOnlyObjectWrapper<Node>) 
            //            FXUtils.invokeGetFieldValue(PopupWindow.class, this, "ownerNode");
            //    owner.set(anchor);
            //    super.show(anchor, screenX, screenY);
            //}

        };
        MenuItem item = new MenuItem("copy to text field");
        menu.getItems().add(item);
        item.setOnAction(copyText);

        label1.setContextMenu(menu);
        // same effect as forcing the owner node 
        // has to be done after the last setting of contextMenuProperty 
        // setting to true was introduced as fix for
        // https://bugs.openjdk.java.net/browse/JDK-8114638
        //FXUtils.invokeGetMethodValue(ContextMenu.class, menu, "setShowRelativeToWindow", Boolean.TYPE, false);

        VBox content = new VBox(10, textNode, textNode2, text, label1);
        return content;

    }

    @Override
    public void start(Stage stage) throws Exception {
        stage.setScene(new Scene(createContent(), 400, 200));
        stage.setTitle(FXUtils.version());
        stage.show();
    }

    public static void main(String[] args) {
        launch(args);
    }

    @SuppressWarnings("unused")
    private static final Logger LOG = Logger
            .getLogger(ContextMenuOwnerSO.class.getName());

}

以上所述是小编给大家介绍的Javafx ContextMenu如何获得单击对象?,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对77isp云服务器技术网的支持!

原文链接:https://77isp.com/post/34202.html

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